Find the Pythagorean triplet whose smallet member is 12.
Answer:
(12,35,37)
- For every natural number m>1, (2m,m2−1,m2+1) is a Pythagorean triplet.
Putting 2m=12, we get m=6.
Thus,
m2−1=62−1=35
m2+1=62+1=37 - Hence, (12,35,37) is a Pythagorean triplet.